Questions: The following table shows the relationship between weight and calories burned per minute for five people. Weight (in pounds) Calories burned per minute ---------------------------------------------- 112 7.25 129 9.15 150 9.85 174 10.25 Mean 182 11.75 Standard Deviation 149.4 9.65 29.51 1.64 Weight is the explanatory variable and has a mean of 149.4 and a standard deviation of 29.51. Calories burned per minute is the response variable and has a mean of 9.65 and a standard deviation of 1.64. The correlation was found to be 0.944. Select the correct slope and y-intercept for the least squares line (answer choices are rounded to the hundredths places).

The following table shows the relationship between weight and calories burned per minute for five people.

 Weight (in pounds)  Calories burned per minute 
----------------------------------------------
 112                7.25                      
 129                9.15                      
 150                9.85                      
 174                10.25                     
 Mean               182                        11.75                    
 Standard Deviation 149.4                      9.65                     
                    29.51                      1.64                     

Weight is the explanatory variable and has a mean of 149.4 and a standard deviation of 29.51. Calories burned per minute is the response variable and has a mean of 9.65 and a standard deviation of 1.64.

The correlation was found to be 0.944. Select the correct slope and y-intercept for the least squares line (answer choices are rounded to the hundredths places).
Transcript text: The following table shows the relationship between weight and calories burned per minute for five people. | Weight (in pounds) | Calories burned per minute | |-------------------|---------------------------| | 112 | 7.25 | | 129 | 9.15 | | 150 | 9.85 | | 174 | 10.25 | | Mean | 182 | 11.75 | | Standard Deviation| 149.4 | 9.65 | | | 29.51 | 1.64 | Weight is the explanatory variable and has a mean of 149.4 and a standard deviation of 29.51. Calories burned per minute is the response variable and has a mean of 9.65 and a standard deviation of 1.64. The correlation was found to be 0.944. Select the correct slope and y-intercept for the least squares line (answer choices are rounded to the hundredths places).
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Solution

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Solution Steps

To find the slope and y-intercept of the least squares line, we use the formulas for the slope (\(b\)) and y-intercept (\(a\)) of the regression line \(y = a + bx\). The slope is calculated using the formula \(b = r \times \frac{\text{std\_dev\_y}}{\text{std\_dev\_x}}\), where \(r\) is the correlation coefficient, \(\text{std\_dev\_y}\) is the standard deviation of the response variable, and \(\text{std\_dev\_x}\) is the standard deviation of the explanatory variable. The y-intercept is calculated using the formula \(a = \text{mean\_y} - b \times \text{mean\_x}\), where \(\text{mean\_y}\) and \(\text{mean\_x}\) are the means of the response and explanatory variables, respectively.

Step 1: Calculate the Slope of the Least Squares Line

To find the slope (\(b\)) of the least squares line, we use the formula: \[ b = r \times \frac{\text{std\_dev\_y}}{\text{std\_dev\_x}} \] Substituting the given values: \[ b = 0.944 \times \frac{1.64}{29.51} \approx 0.05246 \]

Step 2: Calculate the Y-Intercept of the Least Squares Line

The y-intercept (\(a\)) is calculated using the formula: \[ a = \text{mean\_y} - b \times \text{mean\_x} \] Substituting the calculated slope and given means: \[ a = 9.65 - 0.05246 \times 149.4 \approx 1.812 \]

Final Answer

\(\boxed{b \approx \frac{41}{781}}\)

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