Questions: If the half-life of I-131 is 25.4 days, how many moles of I-131 would be left in Mr. Miller's body after 68 days if he was infused with 5.6 grams? (Round your answer to four decimal places)

If the half-life of I-131 is 25.4 days, how many moles of I-131 would be left in Mr. Miller's body after 68 days if he was infused with 5.6 grams?
(Round your answer to four decimal places)
Transcript text: If the half-life of I-131 is 25.4 days, how many moles of I-131 would be left in Mr. Miller's body after 68 days if he was infused with 5.6 grams? (Round your answer to four decimal places)
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Solution

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Solution Steps

Step 1: Determine the Initial Moles of I-131

First, we need to calculate the initial number of moles of I-131. The molar mass of I-131 is approximately 130.9061 g/mol. Given that Mr. Miller was infused with 5.6 grams of I-131, we can calculate the initial moles using the formula:

\[ \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \]

\[ \text{Moles} = \frac{5.6 \, \text{g}}{130.9061 \, \text{g/mol}} \approx 0.0428 \, \text{mol} \]

Step 2: Calculate the Number of Half-Lives

The half-life of I-131 is 25.4 days. We need to determine how many half-lives have passed in 68 days:

\[ \text{Number of Half-Lives} = \frac{68 \, \text{days}}{25.4 \, \text{days/half-life}} \approx 2.6772 \]

Step 3: Calculate the Remaining Moles of I-131

The amount of a substance remaining after a certain number of half-lives can be calculated using the formula:

\[ N = N_0 \left(\frac{1}{2}\right)^n \]

where \(N_0\) is the initial amount, \(n\) is the number of half-lives, and \(N\) is the remaining amount.

\[ N = 0.0428 \, \text{mol} \times \left(\frac{1}{2}\right)^{2.6772} \approx 0.0067 \, \text{mol} \]

Final Answer

The number of moles of I-131 remaining in Mr. Miller's body after 68 days is \(\boxed{0.0067 \, \text{mol}}\).

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