To solve the given problems using the linear model L=0.16t+73.71, we will follow these steps:
a. For predicting the life expectancy of a person born in 2014, we need to calculate t as the number of years after 1980 and then substitute it into the linear equation.
b. To find the birth year when the life expectancy is 78, we will set L=78 and solve for t, then convert t back to the birth year.
c. To estimate the life expectancy in 1976, we will calculate t as the number of years before 1980 (which will be negative) and substitute it into the linear equation.
To predict the life expectancy of a person born in 2014, we calculate t as the number of years after 1980:
t=2014−1980=34
Using the linear model L=0.16t+73.71:
L=0.16×34+73.71=79.15
Thus, the life expectancy of a person born in 2014 is 79.15 years.
To find the birth year when the life expectancy is 78 years, we set L=78 and solve for t:
78=0.16t+73.71
0.16t=78−73.71
t=0.1678−73.71=26.8125
The corresponding birth year is:
Birth Year=1980+26.8125≈2007
Thus, a person born in 2007 will have a life expectancy of 78 years.
To estimate the life expectancy in 1976, we calculate t as the number of years before 1980:
t=1976−1980=−4
Using the linear model L=0.16t+73.71:
L=0.16×(−4)+73.71=73.07
Thus, the life expectancy of a person born in 1976 was 73.07 years.