The first reaction is:
\[ 7 \mathrm{O}_{2}(\mathrm{~g}) + 2 \mathrm{CH}_{3} \mathrm{CH}_{3}(\mathrm{~g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{~g}) + 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \]
To determine if this is a redox reaction, we need to check if there is a change in oxidation states of the elements involved.
- Oxygen (\(\mathrm{O}_2\)) has an oxidation state of 0.
- In \(\mathrm{CO}_2\), oxygen has an oxidation state of -2, and carbon has an oxidation state of +4.
- In \(\mathrm{CH}_3\mathrm{CH}_3\), carbon has an oxidation state of -3 (for each hydrogen, +1).
Since the oxidation states of carbon and oxygen change, this is a redox reaction.
- The reducing agent is the substance that loses electrons (is oxidized). Here, \(\mathrm{CH}_3\mathrm{CH}_3\) (ethane) is oxidized from -3 to +4.
- The oxidizing agent is the substance that gains electrons (is reduced). Here, \(\mathrm{O}_2\) is reduced from 0 to -2.
The second reaction is:
\[ \mathrm{HNO}_{3}(a q) + \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{3} \mathrm{O}^{+}(a q) + \mathrm{NO}_{3}^{-}(a q) \]
To determine if this is a redox reaction, we need to check if there is a change in oxidation states of the elements involved.
- In \(\mathrm{HNO}_3\), nitrogen has an oxidation state of +5.
- In \(\mathrm{NO}_3^-\), nitrogen still has an oxidation state of +5.
Since there is no change in the oxidation states of the elements, this is not a redox reaction.
The third reaction is:
\[ \mathrm{CuSO}_{4}(a q) + \mathrm{Zn}(s) \rightarrow \mathrm{ZnSO}_{4}(a q) + \mathrm{Cu}(s) \]
To determine if this is a redox reaction, we need to check if there is a change in oxidation states of the elements involved.
- In \(\mathrm{CuSO}_4\), copper has an oxidation state of +2.
- In \(\mathrm{Zn}\), zinc has an oxidation state of 0.
- In \(\mathrm{ZnSO}_4\), zinc has an oxidation state of +2.
- In \(\mathrm{Cu}\), copper has an oxidation state of 0.
Since the oxidation states of copper and zinc change, this is a redox reaction.
- The reducing agent is the substance that loses electrons (is oxidized). Here, \(\mathrm{Zn}\) is oxidized from 0 to +2.
- The oxidizing agent is the substance that gains electrons (is reduced). Here, \(\mathrm{Cu}^{2+}\) is reduced from +2 to 0.
For the reaction \( 7 \mathrm{O}_{2}(\mathrm{~g}) + 2 \mathrm{CH}_{3} \mathrm{CH}_{3}(\mathrm{~g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{~g}) + 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \):
- Redox reaction: Yes
- Reducing agent: \(\mathrm{CH}_3\mathrm{CH}_3\)
- Oxidizing agent: \(\mathrm{O}_2\)
\[
\boxed{\text{Redox reaction: Yes, Reducing agent: } \mathrm{CH}_3\mathrm{CH}_3, \text{ Oxidizing agent: } \mathrm{O}_2}
\]
For the reaction \( \mathrm{HNO}_{3}(a q) + \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{3} \mathrm{O}^{+}(a q) + \mathrm{NO}_{3}^{-}(a q) \):
- Redox reaction: No
\[
\boxed{\text{Redox reaction: No}}
\]
For the reaction \( \mathrm{CuSO}_{4}(a q) + \mathrm{Zn}(s) \rightarrow \mathrm{ZnSO}_{4}(a q) + \mathrm{Cu}(s) \):
- Redox reaction: Yes
- Reducing agent: \(\mathrm{Zn}\)
- Oxidizing agent: \(\mathrm{Cu}^{2+}\)
\[
\boxed{\text{Redox reaction: Yes, Reducing agent: } \mathrm{Zn}, \text{ Oxidizing agent: } \mathrm{Cu}^{2+}}
\]