Questions: A 0.750 mol sample of Xe gas is confined in a 18.7 liter container at 30.8°C. If the temperature of the gas sample is lowered to 8.10°C holding the volume constant, the average molecular speed will increase decrease remain the same not enough information to answer the question

A 0.750 mol sample of Xe gas is confined in a 18.7 liter container at 30.8°C. If the temperature of the gas sample is lowered to 8.10°C holding the volume constant, the average molecular speed will increase decrease remain the same not enough information to answer the question
Transcript text: A $\mathbf{0 . 7 5 0}$ mol sample of Xe gas is confined in a $\mathbf{1 8 . 7}$ liter container at $\mathbf{3 0 . 8}{ }^{\circ} \mathrm{C}$. If the temperature of the gas sample is lowered to $8.10^{\circ} \mathrm{C}$ holding the volume constant, the average molecular speed will increase decrease remain the same not enough information to answer the question
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Solution

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Solution Steps

Step 1: Understand the Relationship Between Temperature and Molecular Speed

The average molecular speed of a gas is related to its temperature. According to the kinetic molecular theory, the average speed of gas molecules is proportional to the square root of the absolute temperature (in Kelvin). The formula for the average speed \( v \) of gas molecules is given by:

\[ v \propto \sqrt{T} \]

where \( T \) is the absolute temperature in Kelvin.

Step 2: Convert Temperatures to Kelvin

First, convert the given temperatures from Celsius to Kelvin:

  • Initial temperature: \( 30.8^\circ \mathrm{C} = 30.8 + 273.15 = 303.95 \, \mathrm{K} \)
  • Final temperature: \( 8.1^\circ \mathrm{C} = 8.1 + 273.15 = 281.25 \, \mathrm{K} \)
Step 3: Determine the Effect of Temperature Change on Molecular Speed

Since the average molecular speed is proportional to the square root of the temperature, we can compare the initial and final temperatures to determine the effect on speed:

  • Initial speed is proportional to \( \sqrt{303.95} \)
  • Final speed is proportional to \( \sqrt{281.25} \)

Since \( 281.25 \, \mathrm{K} < 303.95 \, \mathrm{K} \), the square root of the final temperature will be less than the square root of the initial temperature. Therefore, the average molecular speed will decrease.

Final Answer

The average molecular speed will \(\boxed{\text{decrease}}\).

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