The function f(x)=8+x8−x f(x) = \frac{\sqrt{8+x}}{8-x} f(x)=8−x8+x has two restrictions:
To ensure the square root is defined: 8+x≥0 ⟹ x≥−8. 8 + x \geq 0 \implies x \geq -8. 8+x≥0⟹x≥−8.
To ensure the denominator is not zero: 8−x≠0 ⟹ x≠8. 8 - x \neq 0 \implies x \neq 8. 8−x=0⟹x=8.
The domain of f(x) f(x) f(x) is all real numbers x x x such that x≥−8 x \geq -8 x≥−8 and x≠8 x \neq 8 x=8. This can be written as the interval [−8,8)∪(8,∞)[-8, 8) \cup (8, \infty)[−8,8)∪(8,∞).
[−8,8)∪(8,∞) \boxed{[-8, 8) \cup (8, \infty)} [−8,8)∪(8,∞)
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