Questions: Question 8 Sodium Fluoride is a colorless or white compound often used as an insecticide and in toothpastes to prevent tooth decay. After sodium (Na) binds to fluoride (F), what charge is it left with? Sodium -10 -1 +11 +1

Question 8

Sodium Fluoride is a colorless or white compound often used as an insecticide and in toothpastes to prevent tooth decay.
After sodium (Na) binds to fluoride (F), what charge is it left with?
Sodium
-10
-1
+11
+1
Transcript text: Question 8 1 pts Sodium Fluoride is a colorless or white compound often used as an insecticide and in toothpastes to prevent tooth decay. After sodium $(\mathrm{Na})$ binds to fluoride $(\mathrm{F})$, what charge is it left with? Sodium $-10$ $-1$ $+11$ $+1$ Question 9 1 pts
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Solution

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Solution Steps

Step 1: Understanding the Chemical Bonding

Sodium (Na) is an element that belongs to the alkali metals group in the periodic table. It has one electron in its outermost shell, which it tends to lose in order to achieve a stable electron configuration similar to the noble gases.

Step 2: Determining the Charge After Electron Loss

When sodium loses its one valence electron, it becomes a positively charged ion, known as a cation. The loss of one electron results in a charge of \(+1\) because electrons are negatively charged, and losing one results in a net positive charge.

Step 3: Identifying the Correct Charge

Given the options:

  • \(-10\)
  • \(-1\)
  • \(+11\)
  • \(+1\)

The correct charge for sodium after it loses one electron and binds with fluoride is \(+1\).

Final Answer

\(\boxed{+1}\)

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