The results are summarized as follows:
- \( P(X \leq 14) \approx 0.499 \)
- \( P(X = 14) \approx 0.2153 \)
- Mean \( \mu = 14.4 \)
- Variance \( \sigma^2 = 2.88 \)
- Standard Deviation \( \sigma \approx 1.6971 \)
Thus, the final boxed answer is:
\[
\boxed{P(X \leq 14) \approx 0.499, \; P(X = 14) \approx 0.2153, \; \mu = 14.4, \; \sigma^2 = 2.88, \; \sigma \approx 1.6971}
\]