Questions: How many electrons must each of the atoms below lose to achieve a noble gas electron configuration? Li electrons Sr Al electrons Ba What is a polyatomic ion?

How many electrons must each of the atoms below lose to achieve a noble gas electron configuration?

Li  electrons 

Sr   

Al  electrons 

Ba   

What is a polyatomic ion?
Transcript text: How many electrons must each of the atoms below lose to achieve a noble gas electron configuration? \begin{tabular}{|l|l|l|} \hline Li & electrons \\ \hline Sr & & \\ \hline Al & electrons \\ \hline Ba & & \\ \hline \end{tabular} Question 4 2 pts What is a polyatomic ion?
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Solution

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Solution Steps

Step 1: Understanding Noble Gas Electron Configuration

To achieve a noble gas electron configuration, an atom must have the same number of electrons as the nearest noble gas. This typically involves losing or gaining electrons to fill or empty the outermost electron shell.

Step 2: Determine Electrons Lost for Each Atom
  • Li (Lithium): Lithium has 3 electrons. The nearest noble gas is Helium, which has 2 electrons. Therefore, Lithium must lose 1 electron to achieve the noble gas configuration of Helium.
  • Sr (Strontium): Strontium has 38 electrons. The nearest noble gas is Krypton, which has 36 electrons. Therefore, Strontium must lose 2 electrons to achieve the noble gas configuration of Krypton.
  • Al (Aluminum): Aluminum has 13 electrons. The nearest noble gas is Neon, which has 10 electrons. Therefore, Aluminum must lose 3 electrons to achieve the noble gas configuration of Neon.
  • Ba (Barium): Barium has 56 electrons. The nearest noble gas is Xenon, which has 54 electrons. Therefore, Barium must lose 2 electrons to achieve the noble gas configuration of Xenon.

Final Answer

  • Li: \(\boxed{1 \text{ electron}}\)
  • Sr: \(\boxed{2 \text{ electrons}}\)
  • Al: \(\boxed{3 \text{ electrons}}\)
  • Ba: \(\boxed{2 \text{ electrons}}\)
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