Questions: Giving a test to a group of students, the table below summarizes the grade earned by gender. A B C Total ---------------------- Male 20 16 2 38 Female18 4 6 28 Total 38 20 8 66 If one student is chosen at random, find the probability that the student is male given the student earned grade B. Round your answer to four decimal places.

Giving a test to a group of students, the table below summarizes the grade earned by gender.

       A  B  C  Total 
----------------------
 Male  20 16 2   38   
 Female18 4  6   28   
 Total 38 20 8   66   

If one student is chosen at random, find the probability that the student is male given the student earned grade B. Round your answer to four decimal places.
Transcript text: Giving a test to a group of students, the table below summarizes the grade earned by gender. \begin{tabular}{|r|r|r|r|r|} \hline & A & B & C & Total \\ \hline Male & 20 & 16 & 2 & 38 \\ \hline Female & 18 & 4 & 6 & 28 \\ \hline Total & 38 & 20 & 8 & 66 \\ \hline \end{tabular} If one student is chosen at random, find the probability that the student is male given the student earned grade B. Round your answer to four decimal places.
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Solution

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Solution Steps

Step 1: Define the Problem

We need to find the probability that a randomly selected student is male given that the student earned a grade of B. This can be expressed mathematically as:

\[ P(\text{Male} | B) = \frac{P(\text{Male and } B)}{P(B)} \]

Step 2: Calculate \( P(\text{Male and } B) \)

The probability that a student is both male and earned a grade of B is calculated as follows:

\[ P(\text{Male and } B) = \frac{\text{Number of males who got B}}{\text{Total number of students}} = \frac{16}{66} \]

Step 3: Calculate \( P(B) \)

The probability that a student earned a grade of B is given by:

\[ P(B) = \frac{\text{Total number of students who got B}}{\text{Total number of students}} = \frac{20}{66} \]

Step 4: Calculate \( P(\text{Male} | B) \)

Now we can substitute the values into the formula for conditional probability:

\[ P(\text{Male} | B) = \frac{P(\text{Male and } B)}{P(B)} = \frac{\frac{16}{66}}{\frac{20}{66}} = \frac{16}{20} = 0.8 \]

Final Answer

Thus, the probability that the student is male given that the student earned a grade of B is:

\[ \boxed{0.8} \]

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