Questions: 3. Draw structural or line angle formulas of 2 compounds that illustrate cis-trans isomers in alkenes.

Transcript text: 3. Draw structural or line angle formulas of 2 compounds that illustrate cis-trans isomers in alkenes.

Solution

Solution Steps

Step 1: Understanding Cis-Trans Isomerism in Alkenes

Cis-trans isomerism, also known as geometric isomerism, occurs in alkenes due to the restricted rotation around the carbon-carbon double bond. This type of isomerism is possible when each carbon atom of the double bond has two different substituents.

Step 2: Choosing a Suitable Alkene

To illustrate cis-trans isomerism, we can choose 2-butene as an example. In 2-butene, the double bond is between the second and third carbon atoms, and each of these carbons has a methyl group and a hydrogen atom as substituents.

Step 3: Drawing the Structural Formulas

Cis-2-butene: In the cis isomer, the two methyl groups (CH\(_3\)) are on the same side of the double bond.
Trans-2-butene: In the trans isomer, the two methyl groups are on opposite sides of the double bond.

Final Answer

Cis-2-butene: \[ \text{CH}_3\text{-CH}=\text{CH-CH}_3 \] \[ \begin{array}{c} \text{H} \\ \text{|} \\ \text{C} \\ \text{|} \\ \text{CH}_3 \end{array} \quad \begin{array}{c} \text{H} \\ \text{|} \\ \text{C} \\ \text{|} \\ \text{CH}_3 \end{array} \]
Trans-2-butene: \[ \text{CH}_3\text{-CH}=\text{CH-CH}_3 \] \[ \begin{array}{c} \text{H} \\ \text{|} \\ \text{C} \\ \text{|} \\ \text{CH}_3 \end{array} \quad \begin{array}{c} \text{CH}_3 \\ \text{|} \\ \text{C} \\ \text{|} \\ \text{H} \end{array} \]

\[ \boxed{\text{Cis-2-butene and Trans-2-butene}} \]

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