Questions: Solve the exponential equation algebraically. Approximate the result to three decimal places.
2 e^x = 18
Transcript text: Solve the exponential equation algebraically. Approximate the result to three decimal places.
\[
2 e^{x}=18
\]
Solution
Solution Steps
To solve the exponential equation \(2 e^{x} = 18\), we first isolate the exponential term by dividing both sides by 2, resulting in \(e^{x} = 9\). Then, we take the natural logarithm of both sides to solve for \(x\), which gives us \(x = \ln(9)\). Finally, we approximate the result to three decimal places.
Step 1: Isolate the Exponential Term
Starting with the equation:
\[
2 e^{x} = 18
\]
we divide both sides by 2 to isolate the exponential term:
\[
e^{x} = 9
\]
Step 2: Take the Natural Logarithm
Next, we take the natural logarithm of both sides:
\[
\ln(e^{x}) = \ln(9)
\]
Using the property of logarithms, this simplifies to:
\[
x = \ln(9)
\]
Step 3: Approximate the Result
Calculating the natural logarithm, we find:
\[
x \approx 2.1972245773362196
\]
Rounding this to three decimal places gives:
\[
x \approx 2.197
\]