I'll solve this electrical circuit problem step by step.
Find the resistance in a circuit where the voltage is $4+2i$ volts and the current is $-4i$ amperes.
Identify the given values
We are given:
- Voltage $V = 4+2i$ volts
- Current $I = -4i$ amperes
- The resistance formula: $R = \frac{V}{I}$
Calculate the resistance using the formula
$R = \frac{V}{I} = \frac{4+2i}{-4i}$
To divide complex numbers, I'll multiply both numerator and denominator by the complex conjugate of the denominator:
$R = \frac{4+2i}{-4i} \cdot \frac{4i}{4i} = \frac{(4+2i)(4i)}{(-4i)(4i)} = \frac{(4+2i)(4i)}{-16i^2}$
Since $i^2 = -1$, we have:
$R = \frac{(4+2i)(4i)}{-16(-1)} = \frac{(4+2i)(4i)}{16}$
Expand the numerator
$R = \frac{(4)(4i) + (2i)(4i)}{16} = \frac{16i + 8i^2}{16} = \frac{16i + 8(-1)}{16} = \frac{16i - 8}{16}$
Simplify the final expression
$R = \frac{16i - 8}{16} = \frac{-8}{16} + \frac{16i}{16} = -\frac{1}{2} + i$
Therefore, the resistance is $R = -\frac{1}{2} + i$ ohms.
\(\boxed{R = -\frac{1}{2} + i}\)
\(\boxed{R = -\frac{1}{2} + i \text{ ohms}}\)