Questions: II. 93-28= ? Tens Ones -

Transcript text: II. $93-28=$ ? \begin{tabular}{c|c} Tens & Ones \\ \hline$\square$ & $\square$ \\ - & \\ \hline & \\ \hline & \\ \hline \end{tabular}

Solution

Solution Steps

Step 1: Subtract the Ones Place

Subtract the ones place digits: $ 3 - 8 $. Since $ 3 $ is less than $ 8 $, borrow $ 1 $ from the tens place. This makes the ones place $ 13 - 8 = 5 $.

Step 2: Subtract the Tens Place

After borrowing, the tens place becomes $ 8 $ (since $ 9 - 1 = 8 $). Subtract the tens place digits: $ 8 - 2 = 6 $.

Step 3: Write the Final Answer

Combine the results from the tens and ones places to get the final answer: $ 65 $.