The exact values of the six trigonometric functions for the angle \(-690^\circ\) are:
\[
\sin(-690^\circ) = 0.5, \quad \cos(-690^\circ) = \frac{\sqrt{3}}{2}, \quad \tan(-690^\circ) = \frac{1}{\sqrt{3}}, \quad \cot(-690^\circ) = \sqrt{3}, \quad \csc(-690^\circ) = 2, \quad \sec(-690^\circ) = \frac{2}{\sqrt{3}}
\]
Thus, the final boxed answers are:
\[
\boxed{\sin(-690^\circ) = 0.5}
\]
\[
\boxed{\cos(-690^\circ) = \frac{\sqrt{3}}{2}}
\]
\[
\boxed{\tan(-690^\circ) = \frac{1}{\sqrt{3}}}
\]