Questions: Put the following equations in slope intercept forms.
b) -4x+2y=-6
a) -2x+y=12
c) What is the slope of the line 3x+y=-12?
Transcript text: Put the following equations in slope intercept forms.
b) $-4x+2y=-6$
a) $-2x+y=12$
c) What is the slope of the line $3x+y\equiv-12$?
Solution
Solution Steps
To convert the given equations into slope-intercept form, which is \( y = mx + b \), we need to solve each equation for \( y \). This involves isolating \( y \) on one side of the equation. For the third question, we need to identify the slope from the equation once it is in slope-intercept form.
Step 1: Convert the First Equation to Slope-Intercept Form
The first equation is given as \( -2x + y = 12 \). To convert it to slope-intercept form \( y = mx + b \), we solve for \( y \):
\[
y = 2x + 12
\]
Step 2: Convert the Second Equation to Slope-Intercept Form
The second equation is \( -4x + 2y = -6 \). We isolate \( y \) to convert it to slope-intercept form:
\[
2y = 4x - 6 \implies y = 2x - 3
\]
Step 3: Find the Slope of the Third Equation
The third equation is \( 3x + y = -12 \). We rearrange it to find the slope:
\[
y = -3x - 12
\]
From this equation, we can see that the slope \( m \) is \( -3 \).
Final Answer
The slope-intercept forms of the equations are:
\( y = 2x + 12 \)
\( y = 2x - 3 \)
The slope of the line \( 3x + y = -12 \) is \( -3 \).