Questions: Find the range and standard deviation of the set of data. 12,8,7,11,17 The range is 10. (Simplify your answer.) The standard deviation is (Round to the nearest hundredth as needed.)

Find the range and standard deviation of the set of data.
12,8,7,11,17

The range is 10. (Simplify your answer.)
The standard deviation is 
(Round to the nearest hundredth as needed.)
Transcript text: Find the range and standard deviation of the set of data. \[ 12,8,7,11,17 \] The range is 10 . (Simplify your answer.) The standard deviation is $\square$ (Round to the nearest hundredth as needed.)
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Solution

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Solution Steps

Step 1: Calculate the Range

The range of a dataset is calculated as the difference between the maximum and minimum values. For the given data set \( \{12, 8, 7, 11, 17\} \):

\[ \text{Range} = \max(x_i) - \min(x_i) = 17 - 7 = 10 \]

Step 2: Calculate the Mean

The mean \( \mu \) of the dataset is calculated using the formula:

\[ \mu = \frac{\sum x_i}{n} = \frac{12 + 8 + 7 + 11 + 17}{5} = \frac{55}{5} = 11.0 \]

Step 3: Calculate the Variance

The variance \( \sigma^2 \) is calculated using the formula:

\[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{n} \]

Calculating each term:

  • \( (12 - 11)^2 = 1 \)
  • \( (8 - 11)^2 = 9 \)
  • \( (7 - 11)^2 = 16 \)
  • \( (11 - 11)^2 = 0 \)
  • \( (17 - 11)^2 = 36 \)

Summing these values:

\[ \sum (x_i - \mu)^2 = 1 + 9 + 16 + 0 + 36 = 62 \]

Thus, the variance is:

\[ \sigma^2 = \frac{62}{5} = 12.4 \]

Step 4: Calculate the Standard Deviation

The standard deviation \( \sigma \) is the square root of the variance:

\[ \sigma = \sqrt{12.4} \approx 3.52 \]

Final Answer

The range of the data is \( 10 \) and the standard deviation is \( 3.52 \).

\[ \boxed{\text{Range} = 10, \text{Standard Deviation} = 3.52} \]

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