Questions: The young rider on a playground merry-go-round must hold on with a force of 121 N . If the rider's mass is 15.9 kg and the radius of the merry-go-round is 2.33 m , what is the speed of the rider?
Hint•
Transcript text: The young rider on a playground merry-go-round must hold on with a force of 121 N . If the rider's mass is 15.9 kg and the radius of the merry-go-round is 2.33 m , what is the speed of the rider?
Hint•
Solution
Solution Steps
Step 1: Identify the Given Values
We are given the following values:
Force (\( F \)) = 121 N
Mass (\( m \)) = 15.9 kg
Radius (\( r \)) = 2.33 m
Step 2: Understand the Relationship
The force that the rider must hold on with is the centripetal force, which is given by the formula:
\[ F = \frac{mv^2}{r} \]
where \( v \) is the speed of the rider.
Step 3: Solve for Speed
Rearrange the formula to solve for \( v \):
\[ v = \sqrt{\frac{Fr}{m}} \]
Step 4: Substitute the Given Values
Substitute the given values into the equation:
\[ v = \sqrt{\frac{121 \, \text{N} \times 2.33 \, \text{m}}{15.9 \, \text{kg}}} \]
Step 5: Calculate the Speed
Perform the calculation:
\[ v = \sqrt{\frac{282.93}{15.9}} \]
\[ v = \sqrt{17.7994} \]
\[ v \approx 4.2165 \, \text{m/s} \]
Final Answer
The speed of the rider is \(\boxed{4.2165 \, \text{m/s}}\).