Questions: Compute the values of f(x)=(x-7)/(x-1)^2 in the table to the right and use them to determine lim x→1 f(x).

Compute the values of f(x)=(x-7)/(x-1)^2 in the table to the right and use them to determine lim x→1 f(x).
Transcript text: Compute the values of $f(x)=\frac{x-7}{(x-1)^{2}}$ in the table to the right and use them to determine $\lim _{x \rightarrow 1} f(x)$.
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Solution

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Solution Steps

To determine \(\lim_{x \rightarrow 1} f(x)\) for the function \(f(x) = \frac{x-7}{(x-1)^2}\), we can evaluate the function at values of \(x\) that are close to 1 from both the left and the right. By computing \(f(x)\) for values slightly greater than 1 and slightly less than 1, we can observe the behavior of the function as \(x\) approaches 1. This will help us estimate the limit.

Step 1: Evaluate \( f(x) \) for Values Approaching 1

We have the function \( f(x) = \frac{x-7}{(x-1)^2} \). We evaluate this function for values of \( x \) approaching 1 from both sides:

  • For \( x = 1.1 \), \( f(1.1) \approx -590 \)

  • For \( x = 1.01 \), \( f(1.01) \approx -59900 \)

  • For \( x = 1.001 \), \( f(1.001) \approx -5999000 \)

  • For \( x = 1.0001 \), \( f(1.0001) \approx -599990000 \)

  • For \( x = 0.9 \), \( f(0.9) \approx -610 \)

  • For \( x = 0.99 \), \( f(0.99) \approx -60100 \)

  • For \( x = 0.999 \), \( f(0.999) \approx -6001000 \)

  • For \( x = 0.9999 \), \( f(0.9999) \approx -600010000 \)

Step 2: Analyze the Behavior of \( f(x) \)

As \( x \) approaches 1 from both the left (\( x < 1 \)) and the right (\( x > 1 \)), the values of \( f(x) \) become increasingly negative and large in magnitude. This suggests that the function is approaching negative infinity.

Final Answer

The limit of \( f(x) \) as \( x \) approaches 1 is:

\[ \lim_{x \to 1} f(x) = -\infty \]

Thus, the final answer is \(\boxed{-\infty}\).

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