Questions: Factor the following polynomial. 4 x^2-4 x+1 ([?] x-square)^2

Factor the following polynomial.
4 x^2-4 x+1
([?] x-square)^2
Transcript text: Factor the following polynomial. \[ \begin{array}{l} 4 x^{2}-4 x+1 \\ ([?] x-\square)^{2} \end{array} \]
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Solution

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Solution Steps

Step 1: Identify the Polynomial

We start with the polynomial given by:

\[ 4x^2 - 4x + 1 \]

Step 2: Recognize the Perfect Square Trinomial

The polynomial can be recognized as a perfect square trinomial. A perfect square trinomial takes the form:

\[ (a - b)^2 = a^2 - 2ab + b^2 \]

In our case, we can identify:

  • \(a = 2x\) (since \((2x)^2 = 4x^2\))
  • \(b = 1\) (since \(1^2 = 1\))

The middle term \(-4x\) corresponds to \(-2ab\), where \(2ab = 4x\).

Step 3: Factor the Polynomial

Using the identified values of \(a\) and \(b\), we can factor the polynomial as follows:

\[ 4x^2 - 4x + 1 = (2x - 1)^2 \]

Final Answer

Thus, the factored form of the polynomial is:

\[ \boxed{(2x - 1)^2} \]

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