Questions: Find the domain of the function. f(x) = 6/(x-2) + 7/(x-5) The domain of f(x) is

Find the domain of the function.
f(x) = 6/(x-2) + 7/(x-5)

The domain of f(x) is
Transcript text: Find the domain of the function. \[ f(x)=\frac{6}{x-2}+\frac{7}{x-5} \] The domain of $f(x)$ is $\square$
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Solution

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Solution Steps

To find the domain of the function \( f(x) = \frac{6}{x-2} + \frac{7}{x-5} \), we need to determine the values of \( x \) for which the function is defined. The function is undefined where the denominators are zero. Therefore, we need to find the values of \( x \) that make \( x-2 \) and \( x-5 \) equal to zero and exclude these values from the domain.

Solution Approach
  1. Identify the values of \( x \) that make the denominators zero.
  2. Exclude these values from the set of all real numbers to determine the domain.
Step 1: Identify Points of Discontinuity

The function \( f(x) = \frac{6}{x-2} + \frac{7}{x-5} \) is undefined where the denominators are zero. We find the points of discontinuity by solving the equations: \[ x - 2 = 0 \quad \Rightarrow \quad x = 2 \] \[ x - 5 = 0 \quad \Rightarrow \quad x = 5 \]

Step 2: Determine the Domain

The domain of the function consists of all real numbers except the points where the function is undefined. Therefore, we exclude \( x = 2 \) and \( x = 5 \) from the set of real numbers.

Final Answer

The domain of \( f(x) \) is all real numbers except \( 2 \) and \( 5 \): \[ \boxed{\text{All real numbers except } 2 \text{ and } 5} \]

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