Questions: Report Sheet for EXP9 [1] Total Valence Electron Count (show work) (C) ()^-4(2)(C2 H4 Cl2) H^'(4) Cl(7)= 20 valence Electrons [2] Lewis Dot Structure and Draw the structure of any Isomers (same number and types of atoms but different bonding) [3] Molecular Geometry 1. Name 2. Draw the structure 3. Bond Angle Value [4] Polar Bond(s)? [5] Polar or Non-polar molecule? Why? [6] List chemical formulas of molecules with similar geometry and polarity

Report Sheet for EXP9

[1]
Total Valence Electron Count (show work)
(C)
()^-4(2)(C2 H4 Cl2)
H^'(4)
Cl(7)=
20 valence Electrons

[2]
Lewis Dot Structure
and Draw the structure of any Isomers (same number and types of atoms but different bonding)

[3]
Molecular Geometry
1. Name
2. Draw the structure
3. Bond Angle Value

[4]
Polar Bond(s)?

[5]
Polar or Non-polar molecule?
Why?

[6]
List chemical formulas of molecules with similar geometry and polarity
Transcript text: Report Sheet for EXP9 [1] Total Valence Electron Count (show work) (C) ()$^{-4(2)}\left(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{Cl}_{2}\right)$ $H^{\prime}(4)$ $\mathrm{Cl}(7)=$ 20 valence Electrons [2] Lewis Dot Structure and Draw the structure of any Isomers (same number and types of atoms but different bonding) [3] Molecular Geometry 1. Name 2. Draw the structure 3. Bond Angle Value [4] Polar Bond(s)? [5] Polar or Non-polar molecule? Why? [6] List chemical formulas of molecules with similar geometry and polarity
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Solution

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Solution Steps

Step 1: Calculate Total Valence Electron Count for Dichloroethane

To find the total valence electron count for dichloroethane (\(\mathrm{C}_2\mathrm{H}_4\mathrm{Cl}_2\)):

  • Carbon (C) has 4 valence electrons. There are 2 carbon atoms: \(2 \times 4 = 8\).
  • Hydrogen (H) has 1 valence electron. There are 4 hydrogen atoms: \(4 \times 1 = 4\).
  • Chlorine (Cl) has 7 valence electrons. There are 2 chlorine atoms: \(2 \times 7 = 14\).

Total valence electrons: \(8 + 4 + 14 = 26\).

\[ \boxed{26 \text{ valence electrons}} \]

Step 2: Draw Lewis Dot Structure and Isomers for Dichloroethane

The Lewis dot structure for dichloroethane (\(\mathrm{C}_2\mathrm{H}_4\mathrm{Cl}_2\)) is:

\[ \begin{array}{c} \mathrm{H} \\ | \\ \mathrm{H} - \mathrm{C} - \mathrm{C} - \mathrm{H} \\ | \\ \mathrm{Cl} \quad \mathrm{Cl} \end{array} \]

For isomers, dichloroethane can have the following structure:

\[ \begin{array}{c} \mathrm{H} \\ | \\ \mathrm{Cl} - \mathrm{C} - \mathrm{C} - \mathrm{H} \\ | \\ \mathrm{H} \quad \mathrm{Cl} \end{array} \]

\[ \boxed{\text{Lewis Dot Structure and Isomers drawn}} \]

Step 3: Determine Molecular Geometry for Dichloroethane
  1. Name: The molecular geometry around each carbon atom in dichloroethane is tetrahedral.
  2. Draw the structure: The structure is already drawn in Step 2.
  3. Bond Angle Value: The bond angle in a tetrahedral geometry is approximately \(109.5^\circ\).

\[ \boxed{\text{Tetrahedral, Bond Angle } 109.5^\circ} \]

Final Answer

  1. Total Valence Electron Count: \(\boxed{26 \text{ valence electrons}}\)
  2. Lewis Dot Structure and Isomers: \(\boxed{\text{Lewis Dot Structure and Isomers drawn}}\)
  3. Molecular Geometry: \(\boxed{\text{Tetrahedral, Bond Angle } 109.5^\circ}\)
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