Questions: a muon (a subatomic particle with a mass of 1.884 × 10^-25 g) traveling at 315.0 m / s

a muon (a subatomic particle with a mass of 1.884 × 10^-25 g) traveling at 315.0 m / s
Transcript text: a muon (a subatomic particle with a mass of $1.884 \times 10^{-25} \mathrm{~g}$ ) traveling at $315.0 \mathrm{~m} / \mathrm{s}$
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Solution

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Solution Steps

Step 1: Understanding the Problem

The problem involves a muon, which is a subatomic particle with a given mass, traveling at a specified velocity. The task is to interpret the information provided and determine what is being asked. The problem statement seems incomplete, but it provides the mass of the muon and its velocity.

Step 2: Analyzing the Given Data

The mass of the muon is given as \(1.884 \times 10^{-25} \, \text{g}\), and its velocity is \(315.0 \, \text{m/s}\). The problem also mentions "nm" (nanometers), which might imply a conversion or calculation involving distance or wavelength, but the context is unclear.

Step 3: Identifying Potential Calculations

Given the mass and velocity, one possible calculation could be determining the kinetic energy of the muon. The kinetic energy (\(KE\)) of an object can be calculated using the formula:

\[ KE = \frac{1}{2} m v^2 \]

where \(m\) is the mass and \(v\) is the velocity.

Step 4: Calculating the Kinetic Energy

First, convert the mass from grams to kilograms:

\[ m = 1.884 \times 10^{-25} \, \text{g} = 1.884 \times 10^{-28} \, \text{kg} \]

Now, calculate the kinetic energy:

\[ KE = \frac{1}{2} \times 1.884 \times 10^{-28} \, \text{kg} \times (315.0 \, \text{m/s})^2 \]

\[ KE = \frac{1}{2} \times 1.884 \times 10^{-28} \times 99225 \]

\[ KE = 9.348 \times 10^{-24} \, \text{J} \]

Final Answer

The kinetic energy of the muon is \(\boxed{9.348 \times 10^{-24} \, \text{J}}\).

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