We are given the sequence defined by the expression
\[ a_n = \frac{4n - 3}{3n + 5}. \]
To determine the convergence of the sequence as \( n \) approaches infinity, we analyze the limit:
\[ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{4n - 3}{3n + 5}. \]
As \( n \) approaches infinity, we focus on the leading terms in the numerator and denominator:
\[ \lim_{n \to \infty} \frac{4n - 3}{3n + 5} = \lim_{n \to \infty} \frac{4n}{3n} = \frac{4}{3}. \]
The sequence converges, and the limit is
\[ \boxed{\frac{4}{3}}. \]
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