Questions: What is the molarity of a solution with 15.1 g of glucose (molar mass: 180.16 g / mol) dissolved in water to a total volume of 450.0 mL? 0.186

What is the molarity of a solution with 15.1 g of glucose (molar mass: 180.16 g / mol) dissolved in water to a total volume of 450.0 mL?
0.186
Transcript text: Question 5 1.5 pts What is the molarity of a solution with 15.1 g of glucose (molar mass: $180.16 \mathrm{~g} / \mathrm{mol}$ ) dissolved in water to a total volume of 450.0 mL ? \[ 0.186 \]
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Solution

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Solution Steps

Step 1: Calculate the Number of Moles of Glucose

To find the molarity, we first need to calculate the number of moles of glucose. The formula to calculate moles is:

\[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \]

Given:

  • Mass of glucose = 15.1 g
  • Molar mass of glucose = 180.16 g/mol

Substitute the values into the formula:

\[ \text{moles of glucose} = \frac{15.1 \, \text{g}}{180.16 \, \text{g/mol}} = 0.0838 \, \text{mol} \]

Step 2: Convert Volume from mL to L

The volume of the solution is given in milliliters (mL), but molarity is expressed in terms of liters (L). Convert the volume from mL to L:

\[ 450.0 \, \text{mL} = 0.4500 \, \text{L} \]

Step 3: Calculate the Molarity of the Solution

Molarity (\(M\)) is defined as the number of moles of solute per liter of solution. Use the formula:

\[ M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \]

Substitute the values:

\[ M = \frac{0.0838 \, \text{mol}}{0.4500 \, \text{L}} = 0.1862 \, \text{M} \]

Final Answer

The molarity of the solution is \(\boxed{0.1862 \, \text{M}}\).

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