Transcript text: Solve for $\mathrm{x}: \quad \frac{1}{4}(x+2)=\frac{1}{2}(3 x-4)$
Solution
Solution Steps
Step 1: Eliminate the fractions
Multiply both sides of the equation by 4 to eliminate the denominators:
\[
4 \cdot \frac{1}{4}(x+2) = 4 \cdot \frac{1}{2}(3x-4)
\]
Simplify:
\[
(x+2) = 2(3x-4)
\]
Step 2: Expand the right side
Expand the right side of the equation:
\[
x + 2 = 6x - 8
\]
Step 3: Collect like terms
Move all terms involving \( x \) to one side and constants to the other:
\[
x - 6x = -8 - 2
\]
Simplify:
\[
-5x = -10
\]
Step 4: Solve for \( x \)
Divide both sides by \(-5\) to solve for \( x \):
\[
x = \frac{-10}{-5} = 2
\]