To solve this problem using polynomial long division, we need to divide the polynomial x3+7x2−18x−6x^3 + 7x^2 - 18x - 6x3+7x2−18x−6 by x−2x - 2x−2. The result will be in the form q(x)+r(x)d(x)q(x) + \frac{r(x)}{d(x)}q(x)+d(x)r(x), where q(x)q(x)q(x) is the quotient and r(x)r(x)r(x) is the remainder.
We start with the polynomial P(x)=x3+7x2−18x−6 P(x) = x^3 + 7x^2 - 18x - 6 P(x)=x3+7x2−18x−6 and divide it by D(x)=x−2 D(x) = x - 2 D(x)=x−2. Using polynomial long division, we find the quotient and remainder.
The quotient obtained from the division is Q(x)=x2+9x+0 Q(x) = x^2 + 9x + 0 Q(x)=x2+9x+0. This simplifies to Q(x)=x2+9x Q(x) = x^2 + 9x Q(x)=x2+9x.
The remainder from the division is R(x)=−6 R(x) = -6 R(x)=−6.
Thus, we can express the original fraction as: x3+7x2−18x−6x−2=x2+9x+−6x−2 \frac{x^3 + 7x^2 - 18x - 6}{x - 2} = x^2 + 9x + \frac{-6}{x - 2} x−2x3+7x2−18x−6=x2+9x+x−2−6 The final result is: Q(x)=x2+9x,R(x)=−6 \boxed{Q(x) = x^2 + 9x, \quad R(x) = -6} Q(x)=x2+9x,R(x)=−6
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