Questions: Use polynomial long division to rewrite the following fraction in the form q(x)+r(x)/d(x), where d(x) r(x) is the remainder. (x^3+7x^2-18x-6)/(x-2)

Use polynomial long division to rewrite the following fraction in the form q(x)+r(x)/d(x), where d(x) r(x) is the remainder.

(x^3+7x^2-18x-6)/(x-2)
Transcript text: Use polynomial long division to rewrite the following fraction in the form $q(x)+\frac{r(x)}{d(x)}$, where $d(x)$ $r(x)$ is the remainder. \[ \frac{x^{3}+7 x^{2}-18 x-6}{x-2} \]
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Solution

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Solution Steps

To solve this problem using polynomial long division, we need to divide the polynomial x3+7x218x6x^3 + 7x^2 - 18x - 6 by x2x - 2. The result will be in the form q(x)+r(x)d(x)q(x) + \frac{r(x)}{d(x)}, where q(x)q(x) is the quotient and r(x)r(x) is the remainder.

Step 1: Polynomial Long Division

We start with the polynomial P(x)=x3+7x218x6 P(x) = x^3 + 7x^2 - 18x - 6 and divide it by D(x)=x2 D(x) = x - 2 . Using polynomial long division, we find the quotient and remainder.

Step 2: Finding the Quotient

The quotient obtained from the division is Q(x)=x2+9x+0 Q(x) = x^2 + 9x + 0 . This simplifies to Q(x)=x2+9x Q(x) = x^2 + 9x .

Step 3: Finding the Remainder

The remainder from the division is R(x)=6 R(x) = -6 .

Final Answer

Thus, we can express the original fraction as: x3+7x218x6x2=x2+9x+6x2 \frac{x^3 + 7x^2 - 18x - 6}{x - 2} = x^2 + 9x + \frac{-6}{x - 2} The final result is: Q(x)=x2+9x,R(x)=6 \boxed{Q(x) = x^2 + 9x, \quad R(x) = -6}

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