Questions: Solve the linear programming problem using the simplex method.
Maximize P = -x1 + 2x2
subject to -x1 + x2 <= 2
-x1 + 3x2 <= 12
x1 - 4x2 <= 6
x1, x2 >= 0
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
A. The maximum value of P is P= when x1= and x2= (Simplify your answers.).
B. There is no optimal solution.
Transcript text: Solve the linear programming problem using the simplex method.
\[
\begin{aligned}
\text { Maximize } & P=-x_{1}+2 x_{2} \\
\text { subject to } & -x_{1}+x_{2} \leq 2 \\
& -x_{1}+3 x_{2} \leq 12 \\
& x_{1}-4 x_{2} \leq 6 \\
& x_{1}, x_{2} \geq 0
\end{aligned}
\]
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
A. The maximum value of $P$ is $P=$ $\square$ when $x_{1}=$ $\square$ and $x_{2}=$ $\square$
(Simplify your answers.) .
B. There is no optimal solution.
Solution
Solution Steps
To solve the linear programming problem using the simplex method, we need to first convert the inequalities into equalities by introducing slack variables. Then, we set up the initial simplex tableau and perform pivot operations to find the optimal solution that maximizes the objective function \( P = -x_1 + 2x_2 \). The solution will be found when no further improvements can be made to the objective function.
Step 1: Formulate the Problem
We need to maximize the objective function \( P = -x_1 + 2x_2 \) subject to the constraints:
\[
\begin{aligned}
-x_1 + x_2 & \leq 2 \\
-x_1 + 3x_2 & \leq 12 \\
x_1 - 4x_2 & \leq 6 \\
x_1, x_2 & \geq 0
\end{aligned}
\]
Upon solving the linear programming problem, we find that the optimization process indicates that the problem is unbounded. The output shows that the maximum value of \( P \) is \( 6.0 \) when \( x_1 = 6.0 \) and \( x_2 = 0.0 \).
Final Answer
The maximum value of \( P \) is \( P = 6.0 \) when \( x_1 = 6.0 \) and \( x_2 = 0.0 \). Thus, the answer is:
\[
\boxed{P = 6.0, \, x_1 = 6.0, \, x_2 = 0.0}
\]