Questions: round each number: 1. round to nearest ten A) 56 ≈ 60 B) 673 ≈ 670 2. round to nearest Thousand A) 34162 ≈ 34000 B) 6730 ≈ 7000 3. round to nearest Hundred A) 6483 ≈ 6500 B) 273 ≈ 300 Round these numbers : 1) Round to nearest hundred 462 2) Round to nearest ten 74 3) Round to nearest thousand 26548 4) Round to nearest hundred 1732

Solution Steps

To solve the rounding problems, we will use Python's built-in round() function. For each number, we will specify the number of decimal places to round to, which corresponds to the place value (tens, hundreds, thousands) we are interested in.

1. For rounding to the nearest hundred, we will round the number to the nearest multiple of 100.
2. For rounding to the nearest ten, we will round the number to the nearest multiple of 10.
3. For rounding to the nearest thousand, we will round the number to the nearest multiple of 1000.

To round \( 462 \) to the nearest hundred, we observe the tens digit, which is \( 6 \). Since \( 6 \geq 5 \), we round up: \[ 462 \approx 500 \]

To round \( 74 \) to the nearest ten, we look at the units digit, which is \( 4 \). Since \( 4 < 5 \), we round down: \[ 74 \approx 70 \]

To round \( 26548 \) to the nearest thousand, we check the hundreds digit, which is \( 5 \). Since \( 5 \geq 5 \), we round up: \[ 26548 \approx 27000 \]

Final Answer