Questions: Describe the sampling distribution of ( hatp ). Assume the size of the population is 30,000. [ n=900, p=0.8 ] Choose the phrase that best describes the shape of the sampling distribution of ( hatp ) below. A. Approximately normal because ( n leq 0.05 N ) and ( np(1-p)<10 ). B. Not normal because ( n leq 0.05 N ) and ( np(1-p)<10 ). C. Approximately normal because ( n leq 0.05 N ) and ( np(1-p) geq 10 ). D. Not normal because ( n leq 0.05 N ) and ( np(1-p) geq 10 ). Determine the mean of the sampling distribution of ( hatp ). ( muhatp= ) (Round to one decimal place as needed.) Determine the standard deviation of the sampling distribution of ( hatp ). ( sigmahatp= ) (Round to three decimal places as needed.)

Describe the sampling distribution of ( hatp ). Assume the size of the population is 30,000.
[ n=900, p=0.8 ]

Choose the phrase that best describes the shape of the sampling distribution of ( hatp ) below.
A. Approximately normal because ( n leq 0.05 N ) and ( np(1-p)<10 ).
B. Not normal because ( n leq 0.05 N ) and ( np(1-p)<10 ).
C. Approximately normal because ( n leq 0.05 N ) and ( np(1-p) geq 10 ).
D. Not normal because ( n leq 0.05 N ) and ( np(1-p) geq 10 ).

Determine the mean of the sampling distribution of ( hatp ).
( muhatp= ) (Round to one decimal place as needed.)

Determine the standard deviation of the sampling distribution of ( hatp ).
( sigmahatp= ) (Round to three decimal places as needed.)
Transcript text: Describe the sampling distribution of $\hat{p}$. Assume the size of the population is 30,000 . \[ n=900, p=0.8 \] Choose the phrase that best describes the shape of the sampling distribution of $\hat{p}$ below. A. Approximately normal because $n \leq 0.05 \mathrm{~N}$ and $n p(1-p)<10$. B. Not normal because $\mathrm{n} \leq 0.05 \mathrm{~N}$ and $\mathrm{np}(1-\mathrm{p})<10$. C. Approximately normal because $n \leq 0.05 \mathrm{~N}$ and $\mathrm{np}(1-\mathrm{p}) \geq 10$. D. Not normal because $n \leq 0.05 \mathrm{~N}$ and $\mathrm{np}(1-\mathrm{p}) \geq 10$. Determine the mean of the sampling distribution of $\hat{p}$. $\mu_{\hat{p}}=$ $\square$ (Round to one decimal place as needed.) Determine the standard deviation of the sampling distribution of $\hat{p}$. $\sigma_{\hat{p}}=$ $\square$ (Round to three decimal places as needed.)
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Solution

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Solution Steps

Step 1: Determine the Shape of the Sampling Distribution

To assess the shape of the sampling distribution of p^\hat{p}, we check the following conditions:

  1. Condition 1: n0.05Nn \leq 0.05N

    • Here, n=900n = 900 and N=30000N = 30000.
    • Calculation: 0.05×30000=15000.05 \times 30000 = 1500, thus 9001500900 \leq 1500 is satisfied.
  2. Condition 2: np(1p)10np(1-p) \geq 10

    • Calculation: np(1p)=900×0.8×(10.8)=900×0.8×0.2=14410 np(1-p) = 900 \times 0.8 \times (1 - 0.8) = 900 \times 0.8 \times 0.2 = 144 \geq 10
    • This condition is also satisfied.

Since both conditions are met, the sampling distribution of p^\hat{p} is approximately normal.

Step 2: Calculate the Mean of the Sampling Distribution

The mean of the sampling distribution of p^\hat{p} is given by: μp^=p=0.8 \mu_{\hat{p}} = p = 0.8

Step 3: Calculate the Standard Deviation of the Sampling Distribution

The standard deviation of the sampling distribution of p^\hat{p} is calculated using the formula: σp^=p(1p)n=0.8×(10.8)900=0.8×0.2900=0.169000.013 \sigma_{\hat{p}} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.8 \times (1 - 0.8)}{900}} = \sqrt{\frac{0.8 \times 0.2}{900}} = \sqrt{\frac{0.16}{900}} \approx 0.013

Final Answer

  • The shape of the sampling distribution is approximately normal because n0.05Nn \leq 0.05N and np(1p)10np(1-p) \geq 10.
  • The mean of the sampling distribution is μp^=0.8\mu_{\hat{p}} = 0.8.
  • The standard deviation of the sampling distribution is σp^0.013\sigma_{\hat{p}} \approx 0.013.

Thus, the final answers are: Shape: C. Approximately normal because n0.05N and np(1p)10 \text{Shape: } \boxed{\text{C. Approximately normal because } n \leq 0.05N \text{ and } np(1-p) \geq 10} μp^=0.8 \mu_{\hat{p}} = \boxed{0.8} σp^=0.013 \sigma_{\hat{p}} = \boxed{0.013}

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