Questions: What will be the pH of a solution with a hydroxide concentration of 4.3 × 10^-2 M ? - Report your answer to the hundredths place. Provide your answer below: pH=

Solution Steps

First, we need to calculate the pOH of the solution using the hydroxide ion concentration \([OH^-]\). The formula for pOH is:

\[ \text{pOH} = -\log[OH^-] \]

Given: \[ [OH^-] = 4.3 \times 10^{-2} \, \text{M} \]

Substitute the value into the formula:

\[ \text{pOH} = -\log(4.3 \times 10^{-2}) \]

Using a calculator to find the logarithm:

\[ \text{pOH} = -\log(4.3 \times 10^{-2}) \approx -(-1.3674) = 1.3674 \]

Next, we use the relationship between pH and pOH, which is given by:

\[ \text{pH} + \text{pOH} = 14 \]

Rearrange to solve for pH:

\[ \text{pH} = 14 - \text{pOH} \]

Substitute the pOH value:

\[ \text{pH} = 14 - 1.3674 = 12.6326 \]

Finally, we round the pH value to the hundredths place:

\[ \text{pH} \approx 12.63 \]

Final Answer