Questions: A line passes through the point (-1,4) and has a slope of 7. Write an equation in slope-intercept form for this line.
Transcript text: A line passes through the point $(-1,4)$ and has a slope of 7 .
Write an equation in slope-intercept form for this line.
Solution
Solution Steps
To write the equation of a line in slope-intercept form (y = mx + b) given a point and the slope, we can use the point-slope form of the equation of a line, which is \( y - y_1 = m(x - x_1) \). Here, \( m \) is the slope and \( (x_1, y_1) \) is the given point. We can then solve for \( y \) to convert it to slope-intercept form.
Solution Approach
Start with the point-slope form: \( y - y_1 = m(x - x_1) \).
Substitute the given point \((-1, 4)\) and the slope \(7\) into the equation.
Solve for \( y \) to get the equation in slope-intercept form.
Step 1: Identify the Given Information
We are given a point \((-1, 4)\) and a slope \(m = 7\). We need to find the equation of the line in slope-intercept form, which is expressed as \(y = mx + b\).
Step 2: Use the Point-Slope Form
We start with the point-slope form of the equation of a line:
\[
y - y_1 = m(x - x_1)
\]
Substituting the given point \((-1, 4)\) and the slope \(7\):
\[
y - 4 = 7(x + 1)
\]
Step 3: Solve for \(y\)
Now, we simplify the equation to solve for \(y\):
\[
y - 4 = 7x + 7
\]
Adding \(4\) to both sides gives:
\[
y = 7x + 11
\]
Final Answer
The equation of the line in slope-intercept form is
\[
\boxed{y = 7x + 11}
\]