Questions: The graph below shows a rough approximation of what's known as a "flash crash" in the price of the month gold futures on a particular day. Note that t is in hours and p(t) is in dollars. (You can click on a graph to enlarge it.) Evaluate the following. Enter DNE if a limit does not exist or a value is undefined. a. The limit as x approaches 140 of p(t) = 1700 b. The limit as 1 of p(t) = 1800

The graph below shows a rough approximation of what's known as a "flash crash" in the price of the month gold futures on a particular day. Note that t is in hours and p(t) is in dollars. (You can click on a graph to enlarge it.)

Evaluate the following. Enter DNE if a limit does not exist or a value is undefined.
a. The limit as x approaches 140 of p(t) = 1700
b. The limit as 1 of p(t) = 1800
Transcript text: The graph below shows a rough approximation of what's known as a "flash crash" in the price of thime month gold furtures on a particular day, Note that $t$ is in hours and $p(t)$ is in dollars. (You can click on a graph to enlarge it.) Evaluate the following. Enter DNE if a limit does not exist or a value is undefined. a. $\lim _{x \rightarrow 140}(p(t))=1700$ b. $\lim _{1}(p(t))=1800$
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Solution

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Solution Steps

Step 1: Analyze the graph for part (a)

We are asked to find $\lim_{t \rightarrow 14^-} p(t)$. As $t$ approaches 14 from the left, the graph shows the value of $p(t)$ is 1750.

Step 2: Analyze the graph for part (b)

We are asked to find $\lim_{t \rightarrow 14^+} p(t)$. As $t$ approaches 14 from the right, the graph shows the value of $p(t)$ is 1100.

Final Answer

a. \\(\boxed{1750}\\) b. \\(\boxed{1100}\\)

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