Questions: 2. A 0.65 meter long string is stretched to a tension of 3.75 N . A wave with a frequency of 185 Hz and a wavelength of 0.44 m travels on the string. What is the mass of the string?

2. A 0.65 meter long string is stretched to a tension of 3.75 N . A wave with a frequency of 185 Hz and a wavelength of 0.44 m travels on the string. What is the mass of the string?
Transcript text: 2. A 0.65 meter long string is stretched to a tension of 3.75 N . A wave with a frequency of 185 Hz and a wavelength of 0.44 m travels on the string. What is the mass of the string?
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Solution

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Solution Steps

Step 1: Determine the wave speed on the string

The wave speed v v on the string can be calculated using the relationship between frequency f f and wavelength λ \lambda : v=fλ v = f \lambda Given: f=185Hz,λ=0.44m f = 185 \, \text{Hz}, \quad \lambda = 0.44 \, \text{m} v=185×0.44=81.40m/s v = 185 \times 0.44 = 81.40 \, \text{m/s}

Step 2: Relate wave speed to tension and linear mass density

The wave speed on a string is also related to the tension T T and the linear mass density μ \mu by the equation: v=Tμ v = \sqrt{\frac{T}{\mu}} Rearranging to solve for μ \mu : μ=Tv2 \mu = \frac{T}{v^2} Given: T=3.75N,v=81.40m/s T = 3.75 \, \text{N}, \quad v = 81.40 \, \text{m/s} μ=3.75(81.40)2=3.756622.760.0005661kg/m \mu = \frac{3.75}{(81.40)^2} = \frac{3.75}{6622.76} \approx 0.0005661 \, \text{kg/m}

Step 3: Calculate the mass of the string

The mass m m of the string can be found by multiplying the linear mass density μ \mu by the length L L of the string: m=μL m = \mu L Given: L=0.65m L = 0.65 \, \text{m} m=0.0005661×0.650.0003670kg m = 0.0005661 \times 0.65 \approx 0.0003670 \, \text{kg}

Final Answer

m=0.0003670kg \boxed{m = 0.0003670 \, \text{kg}}

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