Questions: Which element has a mass percent composition of 54.50% in Vitamin C, C6H8O6?
Transcript text: Mass percent composition involves calculating the percentage of mass, for each of the individual elements, in a given substance.
Mass percent composition is calculated according to the following equation:
% of an element $=\frac{\text { (number of atoms of element) (atomic mass of element) }}{\text { atomic mass of chemical }} \times 100 \%$
The percentages for each of the individual elements will then add up to $100 \%$.
Which element has a mass percent composition of $54.50 \%$ in Vitamin $\mathrm{C}, \mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}$ ?
Solution
Solution Steps
Step 1: Determine the Molar Mass of Vitamin C
First, we need to calculate the molar mass of Vitamin C, \( \text{C}_6\text{H}_8\text{O}_6 \).
Carbon (C): 6 atoms × 12.01 g/mol = 72.06 g/mol
Hydrogen (H): 8 atoms × 1.008 g/mol = 8.064 g/mol
Oxygen (O): 6 atoms × 16.00 g/mol = 96.00 g/mol
Adding these together gives the molar mass of Vitamin C:
\[
\text{Molar mass of } \text{C}_6\text{H}_8\text{O}_6 = 72.06 + 8.064 + 96.00 = 176.124 \, \text{g/mol}
\]
Step 2: Calculate Mass Percent of Each Element
Next, we calculate the mass percent of each element in Vitamin C using the formula:
\[
\% \text{ of element} = \frac{\text{(number of atoms of element) (atomic mass of element)}}{\text{molar mass of compound}} \times 100\%
\]