Questions: Events A and B are mutually exclusive. Suppose event A occurs with a probability of 0.15 and event B occurs with a probability of 0.4. Compute the following. (a) Compute the probability that B occurs but A does not occur. (b) Compute the probability that either A occurs without B occurring or B occurs without A occurring.

Events A and B are mutually exclusive. Suppose event A occurs with a probability of 0.15 and event B occurs with a probability of 0.4. 
Compute the following.
(a) Compute the probability that B occurs but A does not occur.
(b) Compute the probability that either A occurs without B occurring or B occurs without A occurring.
Transcript text: Events $A$ and $B$ are mutually exclusive. Suppose event $A$ occurs with probability 0.15 and event $B$ occurs with probability 0.4 . Compute the following. (a) Compute the probability that $B$ occurs but $A$ does not occur. (b) Compute the probability that either $A$ occurs without $B$ occurring or $B$ occurs without $A$ occurring.
failed

Solution

failed
failed

Solution Steps

To solve the given problems, we need to use the properties of mutually exclusive events and basic probability rules.

(a) Since events \(A\) and \(B\) are mutually exclusive, the probability that \(B\) occurs but \(A\) does not occur is simply the probability of \(B\) occurring, because \(A\) and \(B\) cannot occur together.

(b) The probability that either \(A\) occurs without \(B\) occurring or \(B\) occurs without \(A\) occurring is the sum of the probabilities of \(A\) and \(B\) occurring, since they are mutually exclusive.

Step 1: Calculate the Probability that \(B\) Occurs but \(A\) Does Not Occur

Since events \(A\) and \(B\) are mutually exclusive, the probability that \(B\) occurs but \(A\) does not occur is given by: \[ P(B \cap \neg A) = P(B) = 0.4 \]

Step 2: Calculate the Probability that Either \(A\) Occurs Without \(B\) Occurring or \(B\) Occurs Without \(A\) Occurring

The probability that either \(A\) occurs without \(B\) occurring or \(B\) occurs without \(A\) occurring is the sum of the probabilities of \(A\) and \(B\): \[ P(A \cap \neg B) + P(B \cap \neg A) = P(A) + P(B) = 0.15 + 0.4 = 0.55 \]

Final Answer

The answers to the sub-questions are:

  • (a) \(P(B \cap \neg A) = 0.4\)
  • (b) \(P(A \cap \neg B) + P(B \cap \neg A) = 0.55\)

Thus, the final answers are: \[ \boxed{P(B \cap \neg A) = 0.4} \] \[ \boxed{P(A \cap \neg B) + P(B \cap \neg A) = 0.55} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful