Questions: General Chemistry 4th Edition McQuarrie · Rock · Gallogly University Science presented by Macmillan A pictorial representation of an electronic configuration is shown. uparrow downarrow/1 s uparrow downarrow/2 s uparrow downarrow/uparrow downarrow/2 p uparrow downarrow uparrow downarrow/3 s uparrow uparrow/3 p- Give the full electron configuration. Do not use the noble gas abbreviation. electron configuration: Name the element, assuming that the configuration describes a neutral atom. element name:

General Chemistry 4th Edition
McQuarrie · Rock · Gallogly
University Science
presented by Macmillan

A pictorial representation of an electronic configuration is shown.

uparrow downarrow/1 s uparrow downarrow/2 s uparrow downarrow/uparrow downarrow/2 p uparrow downarrow uparrow downarrow/3 s uparrow uparrow/3 p-

Give the full electron configuration. Do not use the noble gas abbreviation.
electron configuration:

Name the element, assuming that the configuration describes a neutral atom.
element name:

Transcript text: General Chemistry 4th Edition McQuarrie $\cdot$ Rock $\cdot$ Gallogly University Science presented by Macmillan A pictorial representation of an electronic configuration is shown. \[ \frac{\uparrow \downarrow}{1 s} \frac{\uparrow \downarrow}{2 s} \quad \frac{\uparrow \downarrow}{\frac{\uparrow \downarrow}{2 p} \uparrow \downarrow} \frac{\uparrow \downarrow}{3 s} \quad \uparrow \frac{\uparrow}{3 p}- \] Give the full electron configuration. Do not use the noble gas abbreviation. electron configuration: $\square$ Name the element, assuming that the configuration desscribes a neutral atom. element name: $\square$

Solution

Solution Steps

Step 1: Interpret the Pictorial Representation

The pictorial representation shows the distribution of electrons in atomic orbitals. Each box represents an orbital, and the arrows represent electrons with their spins. The configuration is as follows:

$1s$ orbital: 2 electrons ($\uparrow \downarrow$)
$2s$ orbital: 2 electrons ($\uparrow \downarrow$)
$2p$ orbitals: 6 electrons ($\uparrow \downarrow \uparrow \downarrow \uparrow \downarrow$)
$3s$ orbital: 2 electrons ($\uparrow \downarrow$)
$3p$ orbitals: 3 electrons ($\uparrow \uparrow \uparrow$)

Step 2: Write the Full Electron Configuration

Based on the pictorial representation, the full electron configuration is:

\[ 1s^2 \, 2s^2 \, 2p^6 \, 3s^2 \, 3p^3 \]

Step 3: Identify the Element

The total number of electrons is the sum of the superscripts in the electron configuration:

\[ 2 + 2 + 6 + 2 + 3 = 15 \]

A neutral atom with 15 electrons corresponds to the element with atomic number 15, which is phosphorus (P).