Questions: Based on the diagram below, what is the average velocity of the object if it starts at position A, then goes to B, then goes to C, if this all took 53.15 s to happen.
Transcript text: Based on the diagram below, what is the average velocity of the object if it starts at position $A$, then goes to $B$, then goes to $C$, if this all took 53.15 s to happen.
Solution
Solution Steps
Step 1: Determine the Total Distance Traveled
The object travels from A to B, which is 14.9 meters, and then from B to C, which is 19 meters. The total distance traveled is:
\[ 14.9 \, \text{m} + 19 \, \text{m} = 33.9 \, \text{m} \]
Step 2: Determine the Total Time Taken
The total time taken for the entire journey is given as 53.15 seconds.
Step 3: Calculate the Average Velocity
Average velocity is calculated by dividing the total distance traveled by the total time taken:
\[ \text{Average Velocity} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{33.9 \, \text{m}}{53.15 \, \text{s}} \approx 0.637 \, \text{m/s} \]
Final Answer
The average velocity of the object is approximately \( 0.637 \, \text{m/s} \).