Questions: Si en el circuito de la figura la corriente que circula por la resistencia de 2 ohm es I=2 A, calcule la corriente que circula por la resistencia de 3 ohm 8 / 3 A 2/3A 6 / 3 A 4 / 3 A

Si en el circuito de la figura la corriente que circula por la resistencia de 2 ohm es I=2 A, calcule la corriente que circula por la resistencia de 3 ohm
8 / 3 A
2/3A
6 / 3 A
4 / 3 A

Transcript text: Si en el circuito de la figura la corriente que circula por la resistencia de 2 ohm es $\mathrm{I}=2 \mathrm{~A}$, calcule la corriente que circula por la resistencia de 3 ohm $8 / 3 \mathrm{~A}$ 2/3A $6 / 3 A$ $4 / 3 \mathrm{~A}$

Solution

Solution Steps

Step 1: Identify the given information

The current through the 2-ohm resistor is given as $ I = 2 \, \text{A} $.

Step 2: Calculate the voltage across the 2-ohm resistor

Using Ohm's Law $ V = IR $: \[ V_{2\Omega} = 2 \, \text{A} \times 2 \, \Omega = 4 \, \text{V} \]

Step 3: Determine the voltage across the parallel combination

Since the 2-ohm resistor is in parallel with the 6-ohm resistor, the voltage across the 6-ohm resistor is also $ 4 \, \text{V} $.

Step 4: Calculate the current through the 6-ohm resistor

Using Ohm's Law $ I = \frac{V}{R} $: \[ I_{6\Omega} = \frac{4 \, \text{V}}{6 \, \Omega} = \frac{2}{3} \, \text{A} \]

Step 5: Calculate the total current through the series combination

The total current through the series combination of the 3-ohm resistor and the parallel combination of the 6-ohm and 2-ohm resistors is the sum of the currents through the 6-ohm and 2-ohm resistors: \[ I_{\text{total}} = I_{6\Omega} + I_{2\Omega} = \frac{2}{3} \, \text{A} + 2 \, \text{A} = \frac{8}{3} \, \text{A} \]

Step 6: Calculate the current through the 3-ohm resistor

The current through the 3-ohm resistor is the same as the total current through the series combination: \[ I_{3\Omega} = I_{\text{total}} = \frac{8}{3} \, \text{A} \]