Questions: Si en el circuito de la figura la corriente que circula por la resistencia de 2 ohm es I=2 A, calcule la corriente que circula por la resistencia de 3 ohm 8 / 3 A 2/3A 6 / 3 A 4 / 3 A

Solution Steps

The current through the 2-ohm resistor is given as \( I = 2 \, \text{A} \).

Using Ohm's Law \( V = IR \): \[ V_{2\Omega} = 2 \, \text{A} \times 2 \, \Omega = 4 \, \text{V} \]

Since the 2-ohm resistor is in parallel with the 6-ohm resistor, the voltage across the 6-ohm resistor is also \( 4 \, \text{V} \).

Using Ohm's Law \( I = \frac{V}{R} \): \[ I_{6\Omega} = \frac{4 \, \text{V}}{6 \, \Omega} = \frac{2}{3} \, \text{A} \]

The total current through the series combination of the 3-ohm resistor and the parallel combination of the 6-ohm and 2-ohm resistors is the sum of the currents through the 6-ohm and 2-ohm resistors: \[ I_{\text{total}} = I_{6\Omega} + I_{2\Omega} = \frac{2}{3} \, \text{A} + 2 \, \text{A} = \frac{8}{3} \, \text{A} \]

The current through the 3-ohm resistor is the same as the total current through the series combination: \[ I_{3\Omega} = I_{\text{total}} = \frac{8}{3} \, \text{A} \]

Final Answer