Questions: Use synthetic division to divide (7x^2+6x-7) by (x-1).
Quotient:
Remainder:
Transcript text: Use synthetic division to divide $\left(7 x^{2}+6 x-7\right)$ by $(x-1)$.
Quotient: $\square$
Remainder: $\square$
Solution
Solution Steps
Step 1: Set up the Synthetic Division
Given the polynomial of degree \(n = 2\) with coefficients [7, 6, -7] and divisor \(x \pm 1\).
We perform synthetic division by placing the constant \(k = 1\) to the left and writing down the coefficients in descending order.
Step 2: Perform the Division
We bring down the leading coefficient as is and then multiply \(k\) by the value just written down, placing the result under the next coefficient. We add the values in the current column and write the result beneath, continuing this process for all coefficients.
Step 3: Interpret the Result
The coefficients of the quotient polynomial \(Q(x)\) are [7, 13], starting from \(x^1\) down to \(x^0\), and the last number, 6, represents the remainder.
Final Answer:
The quotient polynomial \(Q(x)\) is 13 + 7x^1 and the remainder is \(6\).