Questions: Part A ICl Spell out the full name of the compound. Part B SF6 Spell out the full name of the compound. Part C I4 O9 Spell out the full name of the compound.

Part A ICl Spell out the full name of the compound. Part B SF6 Spell out the full name of the compound. Part C I4 O9 Spell out the full name of the compound.
Transcript text: Part A ICl Spell out the full name of the compound. Submit Request Answer Part B $\mathrm{SF}_{6}$ Spell out the full name of the compound. Submit Request Answer Part C $\mathrm{I}_{4} \mathrm{O}_{9}$ Spell out the full name of the compound.
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Solution

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Solution Steps

Step 1: Identify the Compound in Part A

The chemical formula given is ICl. This is a binary compound consisting of iodine (I) and chlorine (Cl).

Step 2: Name the Compound in Part A

For binary compounds composed of two nonmetals, the name is typically formed by naming the first element followed by the second element with an "-ide" suffix. Therefore, ICl is named iodine monochloride.

Step 3: Identify the Compound in Part B

The chemical formula given is \(\mathrm{SF}_{6}\). This is a binary compound consisting of sulfur (S) and fluorine (F).

Step 4: Name the Compound in Part B

For \(\mathrm{SF}_{6}\), the name is formed by naming the first element, sulfur, followed by the second element with an "-ide" suffix and a prefix indicating the number of atoms. Since there are six fluorine atoms, the prefix "hexa-" is used. Therefore, \(\mathrm{SF}_{6}\) is named sulfur hexafluoride.

Step 5: Identify the Compound in Part C

The chemical formula given is \(\mathrm{I}_{4} \mathrm{O}_{9}\). This is a compound consisting of iodine (I) and oxygen (O).

Step 6: Name the Compound in Part C

For \(\mathrm{I}_{4} \mathrm{O}_{9}\), the name is formed by naming the first element, iodine, followed by the second element with an "-ide" suffix and a prefix indicating the number of atoms. Since there are four iodine atoms and nine oxygen atoms, the prefixes "tetra-" and "nona-" are used, respectively. Therefore, \(\mathrm{I}_{4} \mathrm{O}_{9}\) is named tetraiodine nonoxide.

Final Answer

  • Part A: \(\boxed{\text{iodine monochloride}}\)
  • Part B: \(\boxed{\text{sulfur hexafluoride}}\)
  • Part C: \(\boxed{\text{tetraiodine nonoxide}}\)
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