Questions: What is the oxidation number of magnesium in MgI2?
Transcript text: What is the oxidation number of magnesium in $\mathrm{MgI}_{2}$ ?
Solution
Solution Steps
Step 1: Identify the compound and its components
The compound given is \(\mathrm{MgI}_{2}\). It consists of magnesium (Mg) and iodine (I).
Step 2: Determine the oxidation number of iodine
Iodine typically has an oxidation number of \(-1\) in compounds.
Step 3: Set up the equation for the oxidation numbers
In \(\mathrm{MgI}_{2}\), there are two iodine atoms. Therefore, the total oxidation number contributed by iodine is:
\[
2 \times (-1) = -2
\]
Step 4: Solve for the oxidation number of magnesium
The sum of the oxidation numbers in a neutral compound must be zero. Let \(x\) be the oxidation number of magnesium. The equation is:
\[
x + (-2) = 0
\]
Solving for \(x\):
\[
x = 2
\]
Final Answer
The oxidation number of magnesium in \(\mathrm{MgI}_{2}\) is \(\boxed{2}\).