Questions: Use the table to answer the question.
(x+3)(x+4)=0
x-3=0 x+4=0
x=3 x=-4
While using the Zero Product Property to find the values of x that make the quadratic equation (x+3)(x+4) equals 0, Oliver completed the work provided in the table. Is Oliver's work accurate? (1 point)
No, he should have a third column where he should set x=0.
No, x-3=0 in the second row should be x+3=0.
Yes, the work is accurate.
No, x+4=0 in the second row should be x-4=0.
Transcript text: Use the table to answer the question.
\[
\begin{array}{c}
(x+3)(x+4)=0 \\
x-3=0 \quad x+4=0 \\
x=3 \quad x=-4
\end{array}
\]
While using the Zero Product Property to find the values of $x$ that make the quadratic equation $(x+3)(x+4)$ equals 0 , Oliver completed the work provided in the table. Is Oliver's work accurate? (1 point)
No, he should have a third column where he should set $x=0$.
No, $x-3=0$ in the second row should be $x+3=0$.
Yes, the work is accurate.
No, $x+4=0$ in the second row should be $x-4=0$.
Solution
Solution Steps
To determine if Oliver's work is accurate, we need to apply the Zero Product Property correctly. The Zero Product Property states that if the product of two factors is zero, then at least one of the factors must be zero. For the equation \((x+3)(x+4)=0\), we should set each factor equal to zero and solve for \(x\). This means setting \(x+3=0\) and \(x+4=0\), and solving these equations will give the correct values of \(x\).
Solution Approach
Apply the Zero Product Property to the equation \((x+3)(x+4)=0\).
Set each factor equal to zero: \(x+3=0\) and \(x+4=0\).
Solve each equation to find the values of \(x\).
Step 1: Apply the Zero Product Property
To solve the equation \((x+3)(x+4)=0\), we apply the Zero Product Property, which states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero:
\(x + 3 = 0\)
\(x + 4 = 0\)
Step 2: Solve Each Equation
Now, we solve each equation for \(x\):
From \(x + 3 = 0\):
\[
x = -3
\]
From \(x + 4 = 0\):
\[
x = -4
\]
Step 3: Verify Oliver's Work
Oliver's work included the equations \(x - 3 = 0\) and \(x + 4 = 0\). The first equation \(x - 3 = 0\) is incorrect because it should be \(x + 3 = 0\). The second equation \(x + 4 = 0\) is correct. Therefore, Oliver's work is not accurate.
Final Answer
The answer is that Oliver's work is not accurate because he incorrectly wrote \(x - 3 = 0\) instead of \(x + 3 = 0\). Thus, the correct conclusion is:
\(\boxed{\text{No, } x - 3 = 0 \text{ in the second row should be } x + 3 = 0.}\)