Questions: Simplify completely into an expression with sin(A) or cos(A) only. You will need to write cos(A) as (cos(A))/1 and add the two fractions. sin(A) tan(A)+cos(A)=

Simplify completely into an expression with sin(A) or cos(A) only. You will need to write cos(A) as (cos(A))/1 and add the two fractions.

sin(A) tan(A)+cos(A)=
Transcript text: Simplify completely into an expression with $\sin (A)$ or $\cos (A)$ only. You will need to write $\cos (A)$ as $\frac{\cos (A)}{1}$ and add the two fractions. \[ \sin (A) \tan (A)+\cos (A)= \]
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Solution

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Solution Steps

To simplify the given expression, we need to express everything in terms of either $\sin(A)$ or $\cos(A)$. We know that $\tan(A) = \frac{\sin(A)}{\cos(A)}$. Substituting this into the expression and then combining the terms will give us the simplified form.

Step 1: Rewrite the Expression

We start with the expression: \[ \sin(A) \tan(A) + \cos(A) \] Substituting \(\tan(A) = \frac{\sin(A)}{\cos(A)}\), we rewrite the expression as: \[ \sin(A) \cdot \frac{\sin(A)}{\cos(A)} + \cos(A) \]

Step 2: Combine the Terms

This simplifies to: \[ \frac{\sin^2(A)}{\cos(A)} + \cos(A) \] To combine these terms, we express \(\cos(A)\) as \(\frac{\cos^2(A)}{\cos(A)}\): \[ \frac{\sin^2(A)}{\cos(A)} + \frac{\cos^2(A)}{\cos(A)} = \frac{\sin^2(A) + \cos^2(A)}{\cos(A)} \]

Step 3: Apply the Pythagorean Identity

Using the Pythagorean identity \(\sin^2(A) + \cos^2(A) = 1\), we can simplify the expression further: \[ \frac{1}{\cos(A)} \]

Final Answer

Thus, the completely simplified expression is: \[ \boxed{\sec(A)} \]

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