Questions: Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by electric transmission lines. A typical high-voltage transmission line is 20 m above the ground and carries a 200 A current at a potential of 110 kV. Part A What is the magnetic field strength on the ground directly under such a transmission line? Express your answer with the appropriate units. B= Value Units

Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by electric transmission lines. A typical high-voltage transmission line is 20 m above the ground and carries a 200 A current at a potential of 110 kV.

Part A

What is the magnetic field strength on the ground directly under such a transmission line?
Express your answer with the appropriate units.

B= Value Units
Transcript text: Although the evidence is weak, there has been concern in recent years over possible health effects from the magnetic fields generated by electric transmission lines. A typical high-voltage transmission line is 20 m above the ground and carries a 200 A current at a potential of 110 kV . Part A What is the magnetic field strength on the ground directly under such a transmission line? Express your answer with the appropriate units. \[ B=\begin{array}{l|l} \text { Value Units } \end{array} \]
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Solution

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Solution Steps

Step 1: Identify the relevant formula

The magnetic field B B generated by a long straight current-carrying wire at a distance r r from the wire is given by the formula: B=μ0I2πr B = \frac{\mu_0 I}{2 \pi r} where:

  • μ0 \mu_0 is the permeability of free space (μ0=4π×107Tm/A \mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} ),
  • I I is the current in the wire,
  • r r is the distance from the wire.
Step 2: Substitute the given values

Given:

  • I=200A I = 200 \, \text{A} ,
  • r=20m r = 20 \, \text{m} .

Substitute these values into the formula: B=(4π×107Tm/A)×200A2π×20m B = \frac{(4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A}) \times 200 \, \text{A}}{2 \pi \times 20 \, \text{m}}

Step 3: Simplify the expression

Simplify the expression by canceling out common terms: B=4×107×2002×20 B = \frac{4 \times 10^{-7} \times 200}{2 \times 20} B=8×10540 B = \frac{8 \times 10^{-5}}{40} B=2×106T B = 2 \times 10^{-6} \, \text{T}

Final Answer

B=2×106T \boxed{B = 2 \times 10^{-6} \, \text{T}}

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