Questions: You wish to test the following claim (H1) at a significance level of α=0.10. Ho: μ=69.9 H1: μ<69.9 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 41.4 37.2 13.9 What is the test statistic for this sample? (Round intermediate values to 2 decimal places. Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null

You wish to test the following claim (H1) at a significance level of α=0.10.

Ho: μ=69.9
H1: μ<69.9

You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data:
data
41.4
37.2
13.9

What is the test statistic for this sample? (Round intermediate values to 2 decimal places. Report answer accurate to three decimal places.)
test statistic = 

What is the p-value for this sample? (Report answer accurate to four decimal places.)
p-value = 

The p-value is...
less than (or equal to) α
greater than α

This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null
Transcript text: You wish to test the following claim $\left(H_{1}\right)$ at a significance level of $\alpha=0.10$. \[ \begin{array}{l} H_{o}: \mu=69.9 \\ H_{1}: \mu<69.9 \end{array} \] You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: \begin{tabular}{|l|} \hline data \\ \hline 41.4 \\ \hline 37.2 \\ \hline 13.9 \\ \hline \end{tabular} What is the test statistic for this sample? (Round intermediate values to 2 decimal places. Report answer accurate to three decimal places.) test statistic = $\square$ What is the p-value for this sample? (Report answer accurate to four decimal places.) p -value = $\square$ The $p$-value is... less than (or equal to) $\alpha$ greater than $\alpha$ This test statistic leads to a decision to... reject the null accept the null fail to reject the null
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Solution

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Solution Steps

Step 1: Calculate Sample Statistics

Given the sample data \( \{41.4, 37.2, 13.9\} \), we calculate the sample mean \( \bar{x} \) and sample standard deviation \( s \):

\[ \bar{x} = \frac{41.4 + 37.2 + 13.9}{3} = 30.8333 \]

\[ s = \sqrt{\frac{(41.4 - 30.8333)^2 + (37.2 - 30.8333)^2 + (13.9 - 30.8333)^2}{3 - 1}} = 14.8143 \]

Step 2: Calculate Standard Error

The standard error \( SE \) is calculated as follows:

\[ SE = \frac{s}{\sqrt{n}} = \frac{14.8143}{\sqrt{3}} = 8.553 \]

Step 3: Calculate Test Statistic

The test statistic \( t \) for the left-tailed test is computed using the formula:

\[ t = \frac{\bar{x} - \mu_0}{SE} = \frac{30.8333 - 69.9}{8.553} = -4.5676 \]

Step 4: Calculate P-value

For a left-tailed test, the p-value is given by:

\[ P = T(z) = 0.0224 \]

Step 5: Decision Based on P-value

We compare the p-value with the significance level \( \alpha = 0.10 \):

Since \( 0.0224 < 0.10 \), we reject the null hypothesis \( H_0 \).

Final Answer

  • Test Statistic: \( t = -4.568 \)
  • P-value: \( 0.0224 \)
  • The p-value is less than (or equal to) \( \alpha \).
  • This test statistic leads to a decision to reject the null.

Thus, the final answers are: \[ \boxed{t = -4.568} \] \[ \boxed{p\text{-value} = 0.0224} \] \[ \text{Decision: reject the null} \]

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