Questions: Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) f(x) = 8x + 2 f(1) = f(-2) = f(1/2) = f(a) = f(-a) = f(a-1) =

Transcript text: 3. [-/6 Points] DETAILS MY NOTES SPRECALC8 2.1.507.XP. ASK YOUR TEACHER PRACTICE ANOTHER Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) \[ \begin{aligned} f(x) & =8 x+2 \\ f(1) & =\square \\ f(-2) & =\square \\ f\left(\frac{1}{2}\right) & =\square \\ f(a) & =\square \\ f(-a) & =\square \\ f(a-1) & =\square \end{aligned} \] Need Help? Read It Submit Answer

Solution

Solution Steps

To evaluate the function \( f(x) = 8x + 2 \) at the indicated values, we will substitute each value into the function and compute the result.

Solution Approach

Substitute \( x = 1 \) into the function and compute \( f(1) \).
Substitute \( x = -2 \) into the function and compute \( f(-2) \).
Substitute \( x = \frac{1}{2} \) into the function and compute \( f\left(\frac{1}{2}\right) \).

Step 1: Evaluate \( f(1) \)

To find \( f(1) \), we substitute \( x = 1 \) into the function: \[ f(1) = 8(1) + 2 = 8 + 2 = 10 \]

Step 2: Evaluate \( f(-2) \)

Next, we evaluate \( f(-2) \) by substituting \( x = -2 \): \[ f(-2) = 8(-2) + 2 = -16 + 2 = -14 \]

Step 3: Evaluate \( f\left(\frac{1}{2}\right) \)

Finally, we evaluate \( f\left(\frac{1}{2}\right) \) by substituting \( x = \frac{1}{2} \): \[ f\left(\frac{1}{2}\right) = 8\left(\frac{1}{2}\right) + 2 = 4 + 2 = 6.0 \]