The polynomial \( f(x) = x^2 - 5x + 6 \) is factorized as follows: \[ f(x) = (x - 3)(x - 2) \]
To find the values of \( x \) for which \( f(x) = 0 \), we set each factor equal to zero: \[ x - 3 = 0 \quad \text{and} \quad x - 2 = 0 \]
Solving the equations from Step 2 gives: \[ x = 3 \quad \text{and} \quad x = 2 \]
The values of \( x \) for which \( f(x) = 0 \) are: \[ x = 2, \quad x = 3 \]
The values of \( x \) for which \( f(x) = 0 \) are \( \boxed{2} \) and \( \boxed{3} \).
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