Questions: Compute the integral from 3 to 5 and from 3 to 4 of (x^2 - 3xy + y^2 + 3x + 5y - 4) dx dy.
Transcript text: Compute $\int_{3}^{5} \int_{3}^{4}\left(x^{2}-3 x y+y^{2}+3 x+5 y-4\right) d x d y$.
Solution
Solution Steps
To solve the given double integral, we will first integrate the function with respect to \(x\) from 3 to 4, and then integrate the resulting expression with respect to \(y\) from 3 to 5. This approach involves evaluating the inner integral first and then using its result to evaluate the outer integral.
Step 1: Define the Function
The function to be integrated is given by:
\[
f(x, y) = x^2 - 3xy + y^2 + 3x + 5y - 4
\]
Step 2: Compute the Inner Integral
First, we integrate \(f(x, y)\) with respect to \(x\) from 3 to 4:
\[
\int_{3}^{4} (x^2 - 3xy + y^2 + 3x + 5y - 4) \, dx
\]
The result of this integration is:
\[
y^2 - \frac{11}{2}y + \frac{113}{6}
\]
Step 3: Compute the Outer Integral
Next, we integrate the result of the inner integral with respect to \(y\) from 3 to 5:
\[
\int_{3}^{5} \left(y^2 - \frac{11}{2}y + \frac{113}{6}\right) \, dy
\]
The result of this integration is:
\[
\frac{79}{3}
\]
Final Answer
The value of the double integral is \(\boxed{\frac{79}{3}}\).