Questions: A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer. (0.27 L)(1 mL / 10^-3 L)(2.08 g / mL) / (60.36 g / mol) = ? Just output the content of the question, DO NOT output additional information or explanations.

A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer. (0.27 L)(1 mL / 10^-3 L)(2.08 g / mL) / (60.36 g / mol) = ? Just output the content of the question, DO NOT output additional information or explanations.
Transcript text: A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer. \[ \frac{(0.27 \mathrm{~L})\left(\frac{1 \mathrm{~mL}}{10^{-3} \mathrm{~L}}\right)\left(2.08 \frac{\mathrm{~g}}{\mathrm{~mL}}\right)}{\left(60.36 \frac{\mathrm{~g}}{\mathrm{~mol}}\right)}=? \] $\square$
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Solution

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Solution Steps

Step 1: Convert Volume from Liters to Milliliters

The given volume is \(0.27 \, \text{L}\). We need to convert this to milliliters using the conversion factor \(1 \, \text{mL} = 10^{-3} \, \text{L}\).

\[ 0.27 \, \text{L} \times \frac{1 \, \text{mL}}{10^{-3} \, \text{L}} = 0.27 \times 10^3 \, \text{mL} = 270 \, \text{mL} \]

Step 2: Calculate the Mass in Grams

Next, we use the density to find the mass. The density is \(2.08 \, \text{g/mL}\).

\[ 270 \, \text{mL} \times 2.08 \, \text{g/mL} = 561.6 \, \text{g} \]

Step 3: Convert Mass to Moles

Finally, we convert the mass to moles using the molar mass \(60.36 \, \text{g/mol}\).

\[ \frac{561.6 \, \text{g}}{60.36 \, \text{g/mol}} = 9.302 \, \text{mol} \]

Final Answer

The units of the student's answer are:

\[ \boxed{\text{mol}} \]

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